Answer
$$3x^2(2x^3-x^2+4x-3)=6x^5-3x^4+12x^3-9x^2$$
Explanation
| $$ \begin{aligned}3x^2(2x^3-x^2+4x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^5-3x^4+12x^3-9x^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x^2} $ by $ \left( 2x^3-x^2+4x-3\right) $ $$ \color{blue}{3x^2} \cdot \left( 2x^3-x^2+4x-3\right) = 6x^5-3x^4+12x^3-9x^2 $$ |
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