Answer
$$3x(5x^2-x+4)=15x^3-3x^2+12x$$
Explanation
| $$ \begin{aligned}3x(5x^2-x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}15x^3-3x^2+12x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x} $ by $ \left( 5x^2-x+4\right) $ $$ \color{blue}{3x} \cdot \left( 5x^2-x+4\right) = 15x^3-3x^2+12x $$ |
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