Answer
$$3a^2b^3(2a^2-7ab+b^2)=6a^4b^3-21a^3b^4+3a^2b^5$$
Explanation
| $$ \begin{aligned}3a^2b^3(2a^2-7ab+b^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6a^4b^3-21a^3b^4+3a^2b^5\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3a^2b^3} $ by $ \left( 2a^2-7ab+b^2\right) $ $$ \color{blue}{3a^2b^3} \cdot \left( 2a^2-7ab+b^2\right) = 6a^4b^3-21a^3b^4+3a^2b^5 $$ |
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