$$ \begin{aligned}3a(x-9)+4(x+9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3ax-27a+4x+36\end{aligned} $$ | |
① | Multiply $ \color{blue}{3a} $ by $ \left( x-9\right) $ $$ \color{blue}{3a} \cdot \left( x-9\right) = 3ax-27a $$Multiply $ \color{blue}{4} $ by $ \left( x+9\right) $ $$ \color{blue}{4} \cdot \left( x+9\right) = 4x+36 $$ |