Answer
$$3(9x^3-4x^2+x^2-2x^2)=27x^3-15x^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3(9x^3-4x^2+x^2-2x^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3(9x^3-5x^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}27x^3-15x^2\end{aligned} $$ | |
| ① | Combine like terms: $$ 9x^3 \color{blue}{-4x^2} + \color{red}{x^2} \color{red}{-2x^2} = 9x^3 \color{red}{-5x^2} $$ |
| ② | Multiply $ \color{blue}{3} $ by $ \left( 9x^3-5x^2\right) $ $$ \color{blue}{3} \cdot \left( 9x^3-5x^2\right) = 27x^3-15x^2 $$ |
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