Answer
$$2b^2-3b-3b^2+6b=-b^2+3b$$
Explanation
| $$ \begin{aligned}2b^2-3b-3b^2+6b& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-b^2+3b\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{2b^2} \color{red}{-3b} \color{blue}{-3b^2} + \color{red}{6b} = \color{blue}{-b^2} + \color{red}{3b} $$ |
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