Answer
$$2a^3(5a^2-7a)+3a^4-a^5=9a^5-11a^4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2a^3(5a^2-7a)+3a^4-a^5& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10a^5-14a^4+3a^4-a^5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9a^5-11a^4\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{2a^3} $ by $ \left( 5a^2-7a\right) $ $$ \color{blue}{2a^3} \cdot \left( 5a^2-7a\right) = 10a^5-14a^4 $$ |
| ② | Combine like terms: $$ \color{blue}{10a^5} \color{red}{-14a^4} + \color{red}{3a^4} \color{blue}{-a^5} = \color{blue}{9a^5} \color{red}{-11a^4} $$ |
This page was created using
Simplify polynomials calculator