Answer
$$20f\cdot2-10-12f=28f-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}20f\cdot2-10-12f& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}40f-10-12f \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}28f-10\end{aligned} $$ | |
| ① | $$ 20 f \cdot 2 = 40 f $$ |
| ② | Combine like terms: $$ \color{blue}{40f} -10 \color{blue}{-12f} = \color{blue}{28f} -10 $$ |
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