$$ \begin{aligned}2(x^2+4x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+8x+2\end{aligned} $$ | |
① | Multiply $ \color{blue}{2} $ by $ \left( x^2+4x+1\right) $ $$ \color{blue}{2} \cdot \left( x^2+4x+1\right) = 2x^2+8x+2 $$ |