$$ \begin{aligned}2(2x^2+6x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2+12x+4\end{aligned} $$ | |
① | Multiply $ \color{blue}{2} $ by $ \left( 2x^2+6x+2\right) $ $$ \color{blue}{2} \cdot \left( 2x^2+6x+2\right) = 4x^2+12x+4 $$ |