$$ \begin{aligned}2(2x)^2+6\cdot2x+2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\cdot4x^2+6\cdot2x+2 \xlongequal{ } \\[1 em] & \xlongequal{ }8x^2+12x+2\end{aligned} $$ | |
① | $$ \left( 2x \right)^2 = 2^2x^2 = 4x^2 $$ |