Answer
$$10\cdot\frac{f^3}{-4f^8}=\frac{10f^3}{-4f^8}$$
Explanation
| $$ \begin{aligned}10 \cdot \frac{f^3}{-4f^8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{10f^3}{-4f^8}\end{aligned} $$ | |
| ① | Multiply $10$ by $ \dfrac{f^3}{-4f^8} $ to get $ \dfrac{ 10f^3 }{ -4f^8 } $. Step 1: Write $ 10 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 10 \cdot \frac{f^3}{-4f^8} & \xlongequal{\text{Step 1}} \frac{10}{\color{red}{1}} \cdot \frac{f^3}{-4f^8} \xlongequal{\text{Step 2}} \frac{ 10 \cdot f^3 }{ 1 \cdot \left( -4f^8 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 10f^3 }{ -4f^8 } \end{aligned} $$ |
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