Answer
$$1.08(a-ay)(bx-ax)=a^2xy-abxy-a^2x+abx$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}1.08(a-ay)(bx-ax)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(1a-ay)(bx-ax) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}abx-a^2x-abxy+a^2xy \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}a^2xy-abxy-a^2x+abx\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{1} $ by $ \left( a-ay\right) $ $$ \color{blue}{1} \cdot \left( a-ay\right) = a-ay $$ |
| ② | Multiply each term of $ \left( \color{blue}{a-ay}\right) $ by each term in $ \left( bx-ax\right) $. $$ \left( \color{blue}{a-ay}\right) \cdot \left( bx-ax\right) = abx-a^2x-abxy+a^2xy $$ |
| ③ | Combine like terms: $$ a^2xy-abxy-a^2x+abx = a^2xy-abxy-a^2x+abx $$ |
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