Answer
$$-x(-2x^2+4x+8)=2x^3-4x^2-8x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-x(-2x^2+4x+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-2x^3+4x^2+8x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^3-4x^2-8x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{x} $ by $ \left( -2x^2+4x+8\right) $ $$ \color{blue}{x} \cdot \left( -2x^2+4x+8\right) = -2x^3+4x^2+8x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-2x^3+4x^2+8x \right) = 2x^3-4x^2-8x $$ |
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