Answer
$$-6(m+4)(m-7)=-6m^2+18m+168$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-6(m+4)(m-7)& \xlongequal{ }-(6m+24)(m-7) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(6m^2-42m+24m-168) \xlongequal{ } \\[1 em] & \xlongequal{ }-(6m^2-18m-168) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6m^2+18m+168\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6m+24}\right) $ by each term in $ \left( m-7\right) $. $$ \left( \color{blue}{6m+24}\right) \cdot \left( m-7\right) = 6m^2-42m+24m-168 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(6m^2-18m-168 \right) = -6m^2+18m+168 $$ |
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