Answer
$$-5(3x^2+4x-4)=-15x^2-20x+20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-5(3x^2+4x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(15x^2+20x-20) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-15x^2-20x+20\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( 3x^2+4x-4\right) $ $$ \color{blue}{5} \cdot \left( 3x^2+4x-4\right) = 15x^2+20x-20 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(15x^2+20x-20 \right) = -15x^2-20x+20 $$ |
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