Answer
$$-3a^2(-2a^2+7a+4a)=6a^4-33a^3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3a^2(-2a^2+7a+4a)& \xlongequal{ }-3a^2(-2a^2+11a) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(-6a^4+33a^3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6a^4-33a^3\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3a^2} $ by $ \left( -2a^2+11a\right) $ $$ \color{blue}{3a^2} \cdot \left( -2a^2+11a\right) = -6a^4+33a^3 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(-6a^4+33a^3 \right) = 6a^4-33a^3 $$ |
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