Answer
$$-3(5x-12)(x-4)=-15x^2+96x-144$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-3(5x-12)(x-4)& \xlongequal{ }-(15x-36)(x-4) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-(15x^2-60x-36x+144) \xlongequal{ } \\[1 em] & \xlongequal{ }-(15x^2-96x+144) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-15x^2+96x-144\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{15x-36}\right) $ by each term in $ \left( x-4\right) $. $$ \left( \color{blue}{15x-36}\right) \cdot \left( x-4\right) = 15x^2-60x-36x+144 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left(15x^2-96x+144 \right) = -15x^2+96x-144 $$ |
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