Answer
$$-2x+5(3x^2-6x-16)=15x^2-32x-80$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-2x+5(3x^2-6x-16)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-2x+15x^2-30x-80 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}15x^2-32x-80\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( 3x^2-6x-16\right) $ $$ \color{blue}{5} \cdot \left( 3x^2-6x-16\right) = 15x^2-30x-80 $$ |
| ② | Combine like terms: $$ \color{blue}{-2x} +15x^2 \color{blue}{-30x} -80 = 15x^2 \color{blue}{-32x} -80 $$ |
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