Answer
$$-(x-3)^2=-x^2+6x-9$$
Explanation
| $$ \begin{aligned}-(x-3)^2& \xlongequal{ }-(x^2-6x+9) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-x^2+6x-9\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left(x^2-6x+9 \right) = -x^2+6x-9 $$ |
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