Answer
$$2\cdot3^2-7^1+3\cdot3^0=14$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2\cdot3^2-7^1+3\cdot3^0& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\cdot9-7+3\cdot1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}18-7+3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}14\end{aligned} $$ | |
| ① | A polynomial raised to the power of one equals itself.A non-zero polynomial raised to the power of 0 equals 1. |
| ② | $$ 2 \cdot 9 = 18 $$ |
| ③ | Combine like terms: $$ \color{blue}{18} \color{red}{-7} + \color{red}{3} = \color{red}{14} $$ |
This page was created using
Simplify polynomials calculator