Answer
$$(z+3)(z+3)=z^2+6z+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(z+3)(z+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}z^2+3z+3z+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}z^2+6z+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{z+3}\right) $ by each term in $ \left( z+3\right) $. $$ \left( \color{blue}{z+3}\right) \cdot \left( z+3\right) = z^2+3z+3z+9 $$ |
| ② | Combine like terms: $$ z^2+ \color{blue}{3z} + \color{blue}{3z} +9 = z^2+ \color{blue}{6z} +9 $$ |
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