Answer
$$(y+6)(y-2)=y^2+4y-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(y+6)(y-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}y^2-2y+6y-12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}y^2+4y-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{y+6}\right) $ by each term in $ \left( y-2\right) $. $$ \left( \color{blue}{y+6}\right) \cdot \left( y-2\right) = y^2-2y+6y-12 $$ |
| ② | Combine like terms: $$ y^2 \color{blue}{-2y} + \color{blue}{6y} -12 = y^2+ \color{blue}{4y} -12 $$ |
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