Question
Answer
$$(x+y-2)(x-11y-8)=x^2-10xy-11y^2-10x+14y+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+y-2)(x-11y-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-10xy-11y^2-10x+14y+16\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+y-2}\right) $ by each term in $ \left( x-11y-8\right) $. $$ \left( \color{blue}{x+y-2}\right) \cdot \left( x-11y-8\right) = x^2-11xy-8x+xy-11y^2-8y-2x+22y+16 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-11xy} \color{red}{-8x} + \color{blue}{xy} -11y^2 \color{green}{-8y} \color{red}{-2x} + \color{green}{22y} +16 = \\ = x^2 \color{blue}{-10xy} -11y^2 \color{red}{-10x} + \color{green}{14y} +16 $$ |
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