$$ \begin{aligned}(x+6)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+12x+36\end{aligned} $$ | |
① | Find $ \left(x+6\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 6 }$. $$ \begin{aligned}\left(x+6\right)^2 = \color{blue}{x^2} +2 \cdot x \cdot 6 + \color{red}{6^2} = x^2+12x+36\end{aligned} $$ |