Answer
$$(x+3)^3=x^3+9x^2+27x+27$$
Explanation
| $$ \begin{aligned}(x+3)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^3+9x^2+27x+27\end{aligned} $$ | |
| ① | Find $ \left(x+3\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = x $ and $ B = 3 $. $$ \left(x+3\right)^3 = x^3+3 \cdot x^2 \cdot 3 + 3 \cdot x \cdot 3^2+3^3 = x^3+9x^2+27x+27 $$ |
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