Answer
$$(x+3)(x-1)=x^2+2x-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+3)(x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-x+3x-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+2x-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+3}\right) $ by each term in $ \left( x-1\right) $. $$ \left( \color{blue}{x+3}\right) \cdot \left( x-1\right) = x^2-x+3x-3 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-x} + \color{blue}{3x} -3 = x^2+ \color{blue}{2x} -3 $$ |
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