Answer
$$(x+3)(2x+3)=2x^2+9x+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x+3)(2x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+3x+6x+9 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2+9x+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x+3}\right) $ by each term in $ \left( 2x+3\right) $. $$ \left( \color{blue}{x+3}\right) \cdot \left( 2x+3\right) = 2x^2+3x+6x+9 $$ |
| ② | Combine like terms: $$ 2x^2+ \color{blue}{3x} + \color{blue}{6x} +9 = 2x^2+ \color{blue}{9x} +9 $$ |
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