Tap the blue circles to see an explanation.
$$ \begin{aligned}(x+1)(x-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-6x+x-6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-5x-6\end{aligned} $$ | |
① | Multiply each term of $ \left( \color{blue}{x+1}\right) $ by each term in $ \left( x-6\right) $. $$ \left( \color{blue}{x+1}\right) \cdot \left( x-6\right) = x^2-6x+x-6 $$ |
② | Combine like terms: $$ x^2 \color{blue}{-6x} + \color{blue}{x} -6 = x^2 \color{blue}{-5x} -6 $$ |