Answer
$$(x-7)(x-5)=x^2-12x+35$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-7)(x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-5x-7x+35 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-12x+35\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-7}\right) $ by each term in $ \left( x-5\right) $. $$ \left( \color{blue}{x-7}\right) \cdot \left( x-5\right) = x^2-5x-7x+35 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-5x} \color{blue}{-7x} +35 = x^2 \color{blue}{-12x} +35 $$ |
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