Answer
$$(x-7)(4x-1)=4x^2-29x+7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-7)(4x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2-x-28x+7 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-29x+7\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-7}\right) $ by each term in $ \left( 4x-1\right) $. $$ \left( \color{blue}{x-7}\right) \cdot \left( 4x-1\right) = 4x^2-x-28x+7 $$ |
| ② | Combine like terms: $$ 4x^2 \color{blue}{-x} \color{blue}{-28x} +7 = 4x^2 \color{blue}{-29x} +7 $$ |
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