Answer
$$(x-6)(2x+10)=2x^2-2x-60$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-6)(2x+10)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+10x-12x-60 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-2x-60\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-6}\right) $ by each term in $ \left( 2x+10\right) $. $$ \left( \color{blue}{x-6}\right) \cdot \left( 2x+10\right) = 2x^2+10x-12x-60 $$ |
| ② | Combine like terms: $$ 2x^2+ \color{blue}{10x} \color{blue}{-12x} -60 = 2x^2 \color{blue}{-2x} -60 $$ |
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