Answer
$$(x-5y)(x+3y)=x^2-2xy-15y^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-5y)(x+3y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+3xy-5xy-15y^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-2xy-15y^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-5y}\right) $ by each term in $ \left( x+3y\right) $. $$ \left( \color{blue}{x-5y}\right) \cdot \left( x+3y\right) = x^2+3xy-5xy-15y^2 $$ |
| ② | Combine like terms: $$ x^2+ \color{blue}{3xy} \color{blue}{-5xy} -15y^2 = x^2 \color{blue}{-2xy} -15y^2 $$ |
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