Answer
$$(x-5)(x+3)=x^2-2x-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-5)(x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+3x-5x-15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-2x-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-5}\right) $ by each term in $ \left( x+3\right) $. $$ \left( \color{blue}{x-5}\right) \cdot \left( x+3\right) = x^2+3x-5x-15 $$ |
| ② | Combine like terms: $$ x^2+ \color{blue}{3x} \color{blue}{-5x} -15 = x^2 \color{blue}{-2x} -15 $$ |
This page was created using
Simplify polynomials calculator