Answer
$$(x-3)(x+4)=x^2+x-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-3)(x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2+4x-3x-12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2+x-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-3}\right) $ by each term in $ \left( x+4\right) $. $$ \left( \color{blue}{x-3}\right) \cdot \left( x+4\right) = x^2+4x-3x-12 $$ |
| ② | Combine like terms: $$ x^2+ \color{blue}{4x} \color{blue}{-3x} -12 = x^2+ \color{blue}{x} -12 $$ |
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