Answer
$$(x-3)(x-8)=x^2-11x+24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(x-3)(x-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-8x-3x+24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-11x+24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x-3}\right) $ by each term in $ \left( x-8\right) $. $$ \left( \color{blue}{x-3}\right) \cdot \left( x-8\right) = x^2-8x-3x+24 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-8x} \color{blue}{-3x} +24 = x^2 \color{blue}{-11x} +24 $$ |
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