Answer
$$(x-8)^2=x^2-16x+64$$
Explanation
| $$ \begin{aligned}(x-8)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-16x+64\end{aligned} $$ | |
| ① | Find $ \left(x-8\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 8 }$. $$ \begin{aligned}\left(x-8\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 8 + \color{red}{8^2} = x^2-16x+64\end{aligned} $$ |
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