$$ \begin{aligned}\frac{x^3-x+6}{x+2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-2x+3\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+2}$. $$ \begin{aligned} \frac{x^3-x+6}{x+2} & =\frac{ \left( x^2-2x+3 \right) \cdot \color{blue}{ \left( x+2 \right) }}{ 1 \cdot \color{blue}{ \left( x+2 \right) }} = \\[1ex] &= \frac{x^2-2x+3}{1} =x^2-2x+3 \end{aligned} $$ |