Answer
$$x^2-2-(3x-5)=x^2-3x+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-2-(3x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-2-3x+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-3x+3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3x-5 \right) = -3x+5 $$ |
| ② | Combine like terms: $$ x^2 \color{blue}{-2} -3x+ \color{blue}{5} = x^2-3x+ \color{blue}{3} $$ |
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