Answer
$$(x^2-1)(2x-3)=2x^3-3x^2-2x+3$$
Explanation
| $$ \begin{aligned}(x^2-1)(2x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^3-3x^2-2x+3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{x^2-1}\right) $ by each term in $ \left( 2x-3\right) $. $$ \left( \color{blue}{x^2-1}\right) \cdot \left( 2x-3\right) = 2x^3-3x^2-2x+3 $$ |
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