Answer
$$(t+4)(t+5)=t^2+9t+20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(t+4)(t+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}t^2+5t+4t+20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}t^2+9t+20\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{t+4}\right) $ by each term in $ \left( t+5\right) $. $$ \left( \color{blue}{t+4}\right) \cdot \left( t+5\right) = t^2+5t+4t+20 $$ |
| ② | Combine like terms: $$ t^2+ \color{blue}{5t} + \color{blue}{4t} +20 = t^2+ \color{blue}{9t} +20 $$ |
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