Answer
$$(t-2)(t-3)=t^2-5t+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(t-2)(t-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}t^2-3t-2t+6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}t^2-5t+6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{t-2}\right) $ by each term in $ \left( t-3\right) $. $$ \left( \color{blue}{t-2}\right) \cdot \left( t-3\right) = t^2-3t-2t+6 $$ |
| ② | Combine like terms: $$ t^2 \color{blue}{-3t} \color{blue}{-2t} +6 = t^2 \color{blue}{-5t} +6 $$ |
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