Answer
$$n^2-3n+14+3n^2+n-25=4n^2-2n-11$$
Explanation
| $$ \begin{aligned}n^2-3n+14+3n^2+n-25& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4n^2-2n-11\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{n^2} \color{red}{-3n} + \color{green}{14} + \color{blue}{3n^2} + \color{red}{n} \color{green}{-25} = \color{blue}{4n^2} \color{red}{-2n} \color{green}{-11} $$ |
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