Answer
$$(m-5)(m-2)=m^2-7m+10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(m-5)(m-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}m^2-2m-5m+10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}m^2-7m+10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{m-5}\right) $ by each term in $ \left( m-2\right) $. $$ \left( \color{blue}{m-5}\right) \cdot \left( m-2\right) = m^2-2m-5m+10 $$ |
| ② | Combine like terms: $$ m^2 \color{blue}{-2m} \color{blue}{-5m} +10 = m^2 \color{blue}{-7m} +10 $$ |
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