$$ \begin{aligned}(k+2)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}k^3+6k^2+12k+8\end{aligned} $$ | |
① | Find $ \left(k+2\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = k $ and $ B = 2 $. $$ \left(k+2\right)^3 = k^3+3 \cdot k^2 \cdot 2 + 3 \cdot k \cdot 2^2+2^3 = k^3+6k^2+12k+8 $$ |