Answer
$$(b+4)(b-2)=b^2+2b-8$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(b+4)(b-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}b^2-2b+4b-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^2+2b-8\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{b+4}\right) $ by each term in $ \left( b-2\right) $. $$ \left( \color{blue}{b+4}\right) \cdot \left( b-2\right) = b^2-2b+4b-8 $$ |
| ② | Combine like terms: $$ b^2 \color{blue}{-2b} + \color{blue}{4b} -8 = b^2+ \color{blue}{2b} -8 $$ |
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