Question
Answer
$$(a-3)(a-4)=a^2-7a+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(a-3)(a-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a^2-4a-3a+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}a^2-7a+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{a-3}\right) $ by each term in $ \left( a-4\right) $. $$ \left( \color{blue}{a-3}\right) \cdot \left( a-4\right) = a^2-4a-3a+12 $$ |
| ② | Combine like terms: $$ a^2 \color{blue}{-4a} \color{blue}{-3a} +12 = a^2 \color{blue}{-7a} +12 $$ |
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