Answer
$$(8p^2+9p-5)(6p-4)=48p^3+22p^2-66p+20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(8p^2+9p-5)(6p-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}48p^3-32p^2+54p^2-36p-30p+20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}48p^3+22p^2-66p+20\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{8p^2+9p-5}\right) $ by each term in $ \left( 6p-4\right) $. $$ \left( \color{blue}{8p^2+9p-5}\right) \cdot \left( 6p-4\right) = 48p^3-32p^2+54p^2-36p-30p+20 $$ |
| ② | Combine like terms: $$ 48p^3 \color{blue}{-32p^2} + \color{blue}{54p^2} \color{red}{-36p} \color{red}{-30p} +20 = 48p^3+ \color{blue}{22p^2} \color{red}{-66p} +20 $$ |
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