Question
Answer
$$8c+3+12(4c-10)=56c-117$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}8c+3+12(4c-10)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8c+3+48c-120 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}56c-117\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{12} $ by $ \left( 4c-10\right) $ $$ \color{blue}{12} \cdot \left( 4c-10\right) = 48c-120 $$ |
| ② | Combine like terms: $$ \color{blue}{8c} + \color{red}{3} + \color{blue}{48c} \color{red}{-120} = \color{blue}{56c} \color{red}{-117} $$ |
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