Answer
$$(7x^2-8x+2)(5x-3)=35x^3-61x^2+34x-6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7x^2-8x+2)(5x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}35x^3-21x^2-40x^2+24x+10x-6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}35x^3-61x^2+34x-6\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7x^2-8x+2}\right) $ by each term in $ \left( 5x-3\right) $. $$ \left( \color{blue}{7x^2-8x+2}\right) \cdot \left( 5x-3\right) = 35x^3-21x^2-40x^2+24x+10x-6 $$ |
| ② | Combine like terms: $$ 35x^3 \color{blue}{-21x^2} \color{blue}{-40x^2} + \color{red}{24x} + \color{red}{10x} -6 = 35x^3 \color{blue}{-61x^2} + \color{red}{34x} -6 $$ |
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